Infosys Code

n = int(input())
A = int(input())
A1 = []
A2= []
A3= []
ans = 0
for i in range(n):
A1.append(int(input()))
for j in range(n):
A2.append(int(input()))
for k in range(n):
A2.append([p[k], b[k]])
a.sort()
for z in a:
if a[0] > N:
break
N += a[1]
ans += 1
print(ans)

Python 3

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Sec 2 - techinal ability

Q1) median of terms
7
C


Q2) avarege of eleven
20
B


Q3) x y means
N p $
C

Q4) Five brothers
B
Muliplex


Q5) harsh
4 days
A


Q6) a fruit
1900
C

Q7) if m n
East
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Q8) if the second
S
D



Infosys exam Answer

Lexographically smallest question code in C++ 17

Number Of Subsequences Code For Infosys

int A[] = {10,13,7,8,14,11};
int n = 6;

int memo[6];//initialized with -1s;

int count(int currIndex){
if (currIndex == n-1) return 1;
if (memo[currIndex] != -1) return memo[currIndex];

int res = 0;
for (int i=currIndex+1 ; i<n ; i++){
if (abss(A[currIndex] - A[i]) <= 3){
res += count(i);
}
}

memo[currIndex] = res;
return res;
}


c++

// Infosys
// N flowers on a Recatangular pana
int ans = 100000000;
void solve(vector<int> a, int n, int k, int index, int sum,
int maxsum)
{
if (k == 1)
{
maxsum = max(maxsum, sum);
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
}
maxsum = max(maxsum, sum);
ans = min(ans, maxsum);
return;
}
sum = 0;
for (int i = index; i < n; i++)
{
sum += a[i];
maxsum = max(maxsum, sum);
solve(a, n, k - 1, i + 1, sum, maxsum);
}
}
int GetMaxBeauty(int N, int K, vector<int> A)
{

solve(A, N, K, 0, 0, 0);
return ans;
}

array AR of size N

perfect_sum(arr, s, result) :
x = [0]*len(arr)
j = len(arr) - 1

while (s > 0) :
x[j] = s % 2
s = s // 2
j -= 1
sum = 0
for i in range(len(arr)) :
if (x[i] == 1) :
sum += arr[i]
if (sum == result) :
print("{",end="");
for i in range(len(arr)) :
if (x[i] == 1) :
print(arr[i],end= ", ");
print("}, ",end="")

def print_subset(arr, K) :
x = pow(2, len(arr))
for i in range(1, x):
perfect_sum(arr, i, K)

# Driver code
arr = [ ]
n = int(input("Enter length of array : "))
s=int(input("Enter sum : "))
for i in range(n):
ele=int(input("Enter element : "))
arr.append(ele)
print_subset(arr, s)

Python

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